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					<description><![CDATA[    MUJ ASSIGNMENT BCA SAMPLE 2025 DCA2101 Computer Oriented Numerical Methods SESSION April 2025 PROGRAM Bachelor of CoMPUTER APPLICATIONS (BCA) SEMESTER III course CODE &#38; NAME DCA2101 Computer Oriented Numerical Methods             Set-I       Q1. Show that (a)     (b)     Ans1.    (a) δμ = ½(∆ + ... <a title="MUJ ASSIGNMENT BCA SAMPLE 2025" class="read-more" href="https://muj.assignmentsupport.in/muj-assignment-bca-sample-2025/" aria-label="Read more about MUJ ASSIGNMENT BCA SAMPLE 2025">Read more</a>]]></description>
										<content:encoded><![CDATA[<body><p><strong> </strong></p>
<p> </p>
<p><strong>MUJ ASSIGNMENT BCA SAMPLE 2025</strong></p>
<p><strong>DCA2101 Computer Oriented Numerical Methods</strong></p>
<table width="100%">
<tbody>
<tr>
<td width="36%"><strong>SESSION</strong></td>
<td width="63%"><strong>April 2025</strong></td>
</tr>
<tr>
<td width="36%"><strong>PROGRAM</strong></td>
<td width="63%"><strong>Bachelor of CoMPUTER APPLICATIONS (BCA)</strong></td>
</tr>
<tr>
<td width="36%"><strong>SEMESTER</strong></td>
<td width="63%"><strong>III</strong></td>
</tr>
<tr>
<td width="36%"><strong>course CODE &amp; NAME</strong></td>
<td width="63%"><strong>DCA2101 Computer Oriented Numerical Methods</strong></td>
</tr>
<tr>
<td width="36%"><strong> </strong></td>
<td width="63%"><strong> </strong></td>
</tr>
<tr>
<td width="36%"><strong> </strong></td>
<td width="63%"><strong> </strong></td>
</tr>
</tbody>
</table>
<p><strong> </strong></p>
<p><strong> </strong></p>
<p><strong>Set-I</strong></p>
<p> </p>
<p> </p>
<p> </p>
<p><strong>Q1. Show that</strong></p>
<p><strong>(a)   </strong></p>
<p><strong> </strong></p>
<p><strong>(b)   </strong></p>
<p><strong> </strong></p>
<p><strong>Ans1.</strong></p>
<p><strong> </strong></p>
<h3><strong> (a) δμ = ½(∆ + </strong><strong>∇</strong><strong>)</strong></h3>
<p> </p>
<h3><strong>Definitions of Finite Differences:</strong></h3>
<p>Let  be a function defined at equally spaced points with interval . Then:</p>
<ul>
<li><strong>Forward Difference Operator (∆):</strong></li>
</ul>
<ul>
<li><strong>Backward Difference Operator (</strong><strong>∇):</strong></li>
</ul>
<p> </p>
<p> </p>
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<p> </p>
<p> </p>
<p><strong> </strong></p>
<p><strong>Q2. Solve the system of equations using Gauss Jacobi’s Method:   </strong></p>
<p><strong>3x + 20y – z = –18,    2x– 3y + 20z = 25,    20x + y – 2z = 17.</strong></p>
<p> </p>
<p><strong>Ans 2.</strong></p>
<h3><strong>Given Equations:</strong></h3>
<p><strong>3x + 20y – z = –18</strong> 2. <strong>2x – 3y + 20z = 25</strong> 3. <strong>20x + y – 2z = 17</strong></p>
<p> </p>
<h3><strong>Step 1: Rearranging equations to isolate each variable</strong></h3>
<p>We rewrite each equation to express <strong>x, y, z</strong> in terms of the other variables:</p>
<h4>Equation (1):</h4>
<h4>Equation (2):</h4>
<p> </p>
<p> </p>
<p><strong>Q3. Fit straight line of the form </strong> <strong>, to the following data by method of moment</strong></p>
<table width="100%">
<tbody>
<tr>
<td width="20%"></td>
<td width="20%"><strong>2</strong></td>
<td width="20%"><strong>3</strong></td>
<td width="20%"><strong>4</strong></td>
<td width="20%"><strong>5</strong></td>
</tr>
<tr>
<td width="20%"></td>
<td width="20%"><strong>27</strong></td>
<td width="20%"><strong>40</strong></td>
<td width="20%"><strong>55</strong></td>
<td width="20%"><strong>68</strong></td>
</tr>
</tbody>
</table>
<p><strong>Ans 3.</strong></p>
<p>To fit a straight line of the form:</p>
<p>using the method of moments, we’ll follow a process that matches the first and second moments of the actual data with the corresponding moments of the fitted line.</p>
<h3> <strong>Step 1: Given Data</strong></h3>
<table width="100%">
<thead>
<tr>
<td width="42%">x</td>
<td width="57%">y</td>
</tr>
</thead>
<tbody>
<tr>
<td width="42%">2</td>
<td width="57%">27</td>
</tr>
<tr>
<td width="42%">3</td>
<td width="57%">40</td>
</tr>
<tr>
<td width="42%">4</td>
<td width="57%">55</td>
</tr>
<tr>
<td width="42%">5</td>
<td width="57%">68</td>
</tr>
</tbody>
</table>
<p>Let <strong>n = 4</strong> (number of observations)</p>
<h3><strong>Step 2: Calculate Required Summations</strong></h3>
<p> </p>
<p><strong>Set-II</strong></p>
<p> </p>
<p> </p>
<p><strong>Q4. Apply Gauss forward formula to obtain the value of f(x) at x = 3.5 from the table:</strong></p>
<table width="100%">
<tbody>
<tr>
<td width="18%"></td>
<td width="19%"><strong>1.5</strong></td>
<td width="19%"><strong>2.5</strong></td>
<td width="19%"><strong>3.5</strong></td>
<td width="22%"><strong>4.5</strong></td>
</tr>
<tr>
<td width="18%"></td>
<td width="19%"><strong>8.963</strong></td>
<td width="19%"><strong>24.364</strong></td>
<td width="19%"><strong>66.340</strong></td>
<td width="22%"><strong>180.034</strong></td>
</tr>
</tbody>
</table>
<p><strong>Ans 4.</strong></p>
<p>To apply the Gauss Forward Interpolation Formula, we first construct the forward difference table and then apply the formula to find .</p>
<h3><strong>Given Table:</strong></h3>
<table width="100%">
<thead>
<tr>
<td width="34%">x</td>
<td width="65%">f(x)</td>
</tr>
</thead>
<tbody>
<tr>
<td width="34%">1.5</td>
<td width="65%">8.963</td>
</tr>
<tr>
<td width="34%">2.5</td>
<td width="65%">24.364</td>
</tr>
<tr>
<td width="34%">3.5</td>
<td width="65%">66.340</td>
</tr>
<tr>
<td width="34%">4.5</td>
<td width="65%">180.034</td>
</tr>
</tbody>
</table>
<p>Let’s denote:</p>
<p> </p>
<p> </p>
<p> </p>
<p><strong>Q5. Evaluate </strong> <strong> using the </strong></p>
<ul>
<li><strong>(i) </strong><strong>Simpson’s 3/8 Rule</strong></li>
<li><strong>(ii) </strong><strong>Simpson’s 1/3 Rule</strong></li>
<li><strong>Trapezoidal Rule</strong></li>
</ul>
<p><strong>Ans 5.</strong></p>
<p>To evaluate the integral</p>
<p>using Simpson’s 3/8 Rule, Simpson’s 1/3 Rule, and the Trapezoidal Rule, we need to follow numerical integration steps with a chosen number of sub-intervals n.</p>
<p> </p>
<h3>Step 1: Function and Interval</h3>
<p>Let:</p>
<p><strong>Q6. Find the solution for </strong> <strong> taking interval length 0.1 using Euler’s method to solve: </strong> <strong>    given </strong> <strong>.</strong></p>
<p><strong>Ans 6.</strong></p>
<p>To solve the differential equation</p>
<p>using <strong>Euler’s method</strong> with <strong>step size </strong>  and find the solution at , follow the steps below:</p>
<p> </p>
<h3> <strong>Given:</strong></h3>
<ul>
<li>Differential equation:</li>
<li>Initial condition:</li>
<li>Step size:</li>
</ul>
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